1) Use the data from the CRC Handbook to calculate the ENTHALPY as a function of temperature for pure Al in both the liquid and solid phases over a temperature range of 700 K - 1200 K. Plot the two functions, and determine the latent heat of fusion by calculating the difference in the enthalpies of the two phases at the equilibrium melting temperature.
2) Using the equation for the enthalpy of mixing we derived in class, plot the value of the mixing enthalpy as a function of composition. Assume that you have one mole of a regular solid solution with a BCC crystal structure, with e positive, and taking values of 5 kJ/mole, 50 kJ/mole, and 500 kJ/mole.
3) Calculate the Gibbs free energy as a function of temperature for solid Al over the temperature range of 700 K - 1200 K using BOTH the CRC Handbook Data, and the CALPHAD data (for FCC Al). Plot both curves on the same plot and describe how well they compare to one another. (NOTE: Remember to convert to consistent units between the two graphs. I recommend using J/mole.)
4) Assuming a random binary solution, plot the values of the fraction of AA bonds (fAA), fBB, and fAB versus composition.
None this week.
5) Use the CALPHAD data for liquid and solid (FCC) Al to calculate the Gibbs free energy and find the equilibrium melting temperature of Al.
1) Use the data from the CRC Handbook to calculate the ENTHALPY as a function of temperature for pure Al in both the liquid and solid phases over a temperature range of 700 K - 1200 K. Plot the two functions, and determine the latent heat of fusion by calculating the difference in the enthalpies of the two phases at the equilibrium melting temperature.
From the preface page to the CRC Handbook data, we see that equation 2 gives us the fitting function for the enthalpy as a function of temperature:
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I plugged the correct values into an EXCEL spreadsheet and found the following plots:

My calculated values of the enthalpy at Tm = 933.2 K are H(solid Al) = 1717.1 cal/g-mole, and H(liquid Al) = 6202.4 cal/g-mole, so that the DELTA H = Latent Heat = 4.49 kcal/g-mole.
Just to put this in perspective, if you calculate the specific heat of the solid Al at the melting point (again using the CRC data) and divide that into the latent heat, you have an estimate of the temperature rise that much energy would create if it were all dumped into the solid Al at one time (the latent heat is released during the freezingof the liquid). The answer is a whopping 585 K temperature rise! The message here is that the heats of transition can be BIG, and also that we have to allow time to remove the heat during the freezing process, which gets into solidification processes and casting.
2) Using the equation for the enthalpy of mixing we derived in class, plot the value of the mixing enthalpy as a function of composition. Assume that you have one mole of a regular solid solution with a BCC crystal structure, with e positive, and taking values of 5 kJ/mole, 50 kJ/mole, and 500 kJ/mole.
The BCC structure tells us that the number of nearest neighbors, z = 8. Now we plug and chug and plot:
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3) By my calculations, the two results come out pretty much the same...

4) Assuming a random binary solution, plot the values of the fraction of AA bonds (fAA), fBB, and fAB versus composition. The equations from class used to calculate the fraction of each bond type are:
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ME481 Extra Problem: (ME 481 students must do this in addition to the above set).
ME581 Extra Problem: (ME 581 students must do this in addition to the above set).

I found the temperature at which they are equal is between 930 and 940 K on my plot, good agreement with the listed value of 933.6 K.